What is the foci (y^2)/4-(x^2)/9 =1 ?

The foci (y^2)/4-(x^2)/9 =1 is (0,sqrt(13)),(0,-sqrt(13))

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foci (y^2)/4-(x^2)/9 =1

foci

\frac{y ^{2}}{4} - \frac{x ^{2}}{9} = 1

(0, 13), (0, - 13)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{4} - \frac{x ^{2}}{9} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 2^{2} + 3^{2} : 13

(0, 0 + 13), (0, 0 - 13)

Refine

(0, 13), (0, - 13)

\frac{( x - 5 ) ^{2}}{1} - \frac{( y - 4 ) ^{2}}{1} = 1

9 x^{2} - 4 y^{2} - 54 x - 8 y + 113 = 0

\frac{( y - 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{16} = 1

x^{2} - 3 y^{2} + 12 = 0

9 x^{2} - 9 y^{2} - 18 x + 54 = 0

What is the foci (y^2)/4-(x^2)/9 =1 ?
The foci (y^2)/4-(x^2)/9 =1 is (0,sqrt(13)),(0,-sqrt(13))