What is the foci-x^2+y^2=1 ?

The foci-x^2+y^2=1 is (0,sqrt(2)),(0,-sqrt(2))

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foci-x^2+y^2=1

foci

- x^{2} + y^{2} = 1

(0, 2), (0, - 2)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

- x^{2} + y^{2} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 1, b = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1^{2} + 1^{2} : 2

(0, 0 + 2), (0, 0 - 2)

Refine

(0, 2), (0, - 2)

9 (y - 2)^{2} - 4 x^{2} = 36

\frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0