What is the vertices (y^2)/4-(x^2)/4 =1 ?

The vertices (y^2)/4-(x^2)/4 =1 is (0,2),(0,-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices (y^2)/4-(x^2)/4 =1

vertices

\frac{y ^{2}}{4} - \frac{x ^{2}}{4} = 1

(0, 2), (0, - 2)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{y ^{2}}{4} - \frac{x ^{2}}{4} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 2

(0, 0 + 2), (0, 0 - 2)

Refine

(0, 2), (0, - 2)

x^{2} + 5 x - y^{2} + 3 y = 1

9 x^{2} - 4 y^{2} + 36 x + 8 y + 33 = 0

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

y^{2} - 9 x^{2} = 4

\frac{( x - 3 ) ^{2}}{49} - \frac{( y - 2 ) ^{2}}{16} = 1

What is the vertices (y^2)/4-(x^2)/4 =1 ?
The vertices (y^2)/4-(x^2)/4 =1 is (0,2),(0,-2)