What is the vertices 11x^2-25y^2+22x+250y-889=0 ?

The vertices 11x^2-25y^2+22x+250y-889=0 is (4,5),(-6,5)

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vertices 11x^2-25y^2+22x+250y-889=0

vertices

11 x^{2} - 25 y^{2} + 22 x + 250 y - 889 = 0

(4, 5), (- 6, 5)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

11 x^{2} - 25 y^{2} + 22 x + 250 y - 889 = 0 :

Right-left Hyperbola with

(h, k) = (- 1, 5), a = 5, b = 11

(- 1 + 5, 5), (- 1 - 5, 5)

Refine

(4, 5), (- 6, 5)

4 x^{2} - 45 y^{2} = 180

\frac{x ^{2}}{16} - \frac{y ^{2}}{48} = 1

x^{2} - 9 y^{2} = 144

4 y^{2} - x^{2} + 2 x + 16 y + 7 = 0

4 x^{2} - 9 y^{2} + 32 x + 36 y + 64 = 0

What is the vertices 11x^2-25y^2+22x+250y-889=0 ?
The vertices 11x^2-25y^2+22x+250y-889=0 is (4,5),(-6,5)