What is the vertices 2x^2-y^2-2y=-5 ?

The vertices 2x^2-y^2-2y=-5 is (0,-1+sqrt(6)),(0,-1-sqrt(6))

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vertices 2x^2-y^2-2y=-5

vertices

2 x^{2} - y^{2} - 2 y = - 5

(0, - 1 + 6), (0, - 1 - 6)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

2 x^{2} - y^{2} - 2 y = - 5 :

Up-down Hyperbola with

(h, k) = (0, - 1), a = 6, b = 3

(0, - 1 + 6), (0, - 1 - 6)

9 y^{2} + 36 y - 4 x^{2} - 24 x - 36 = 0

\frac{( x - 8 ) ^{2}}{4} - \frac{( y - 5 ) ^{2}}{9} = 1

x^{2} - y^{2} = 4 x

x^{2} - 6 x - 2 y^{2} + 7 = 0

4 y^{2} - 25 x^{2} = 100

What is the vertices 2x^2-y^2-2y=-5 ?
The vertices 2x^2-y^2-2y=-5 is (0,-1+sqrt(6)),(0,-1-sqrt(6))