What is the vertices-25x^2+4y^2=100 ?

The vertices-25x^2+4y^2=100 is (0,5),(0,-5)

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vertices-25x^2+4y^2=100

vertices

- 25 x^{2} + 4 y^{2} = 100

(0, 5), (0, - 5)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

- 25 x^{2} + 4 y^{2} = 100 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 2

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{y ^{2}}{144} - \frac{x ^{2}}{25} = 1

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{4} = 1

\frac{( x + 1 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{8} = 1

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

\frac{x ^{2}}{36} - \frac{y ^{2}}{25} = 1

What is the vertices-25x^2+4y^2=100 ?
The vertices-25x^2+4y^2=100 is (0,5),(0,-5)