What is the vertices 9x^2-16y^2-18x-64y-199=0 ?

The vertices 9x^2-16y^2-18x-64y-199=0 is (5,-2),(-3,-2)

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vertices 9x^2-16y^2-18x-64y-199=0

vertices

9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0

(5, - 2), (- 3, - 2)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0 :

Right-left Hyperbola with

(h, k) = (1, - 2), a = 4, b = 3

(1 + 4, - 2), (1 - 4, - 2)

Refine

(5, - 2), (- 3, - 2)

x^{2} - 9 y^{2} = 9

\frac{( y + 4 ) ^{2}}{9} - \frac{( x + 2 ) ^{2}}{4} = 1

x^{2} - 3 y^{2} - 2 x - 6 y + 7 = 0

\frac{x ^{2}}{29} - \frac{y ^{2}}{20} = 1

y^{2} - x^{2} = \frac{9}{25}

What is the vertices 9x^2-16y^2-18x-64y-199=0 ?
The vertices 9x^2-16y^2-18x-64y-199=0 is (5,-2),(-3,-2)