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Popular >

vertices 4x^2-y^2=4

Solution

vertices

4 x^{2} - y^{2} = 4

Solution

(1, 0), (- 1, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

4 x^{2} - y^{2} = 4 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 1, b = 2

(0 + 1, 0), (0 - 1, 0)

Refine

(1, 0), (- 1, 0)

Popular Examples

vertices 2x^2-2y^2-20x+16y-16=0 vertices

2 x^{2} - 2 y^{2} - 20 x + 16 y - 16 = 0

vertices-9x^2+4y^2=36 vertices

- 9 x^{2} + 4 y^{2} = 36

vertices ((x-1)^2)/4-((y+3)^2)/(16)=1 vertices

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{16} = 1

vertices ((y+1)^2)/(25)-((x+4)^2)/(64)=1 vertices

\frac{( y + 1 ) ^{2}}{25} - \frac{( x + 4 ) ^{2}}{64} = 1

vertices x^2-y^2-6x=16 vertices

x^{2} - y^{2} - 6 x = 16

Frequently Asked Questions (FAQ)

What is the vertices 4x^2-y^2=4 ?
The vertices 4x^2-y^2=4 is (1,0),(-1,0)