What is the vertices 25y^2-9x^2=225 ?

The vertices 25y^2-9x^2=225 is (0,3),(0,-3)

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vertices 25y^2-9x^2=225

vertices

25 y^{2} - 9 x^{2} = 225

(0, 3), (0, - 3)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

25 y^{2} - 9 x^{2} = 225 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 3, b = 5

(0, 0 + 3), (0, 0 - 3)

Refine

(0, 3), (0, - 3)

9 x^{2} - y^{2} = 36

\frac{( x + 4 ) ^{2}}{4} - (y - 1)^{2} = 1

\frac{x ^{2}}{4} - \frac{y ^{2}}{36} = 1

9 x^{2} - 36 x - 4 y^{2} = 0

\frac{1}{144} x^{2} - \frac{1}{196} y^{2} = 1

What is the vertices 25y^2-9x^2=225 ?
The vertices 25y^2-9x^2=225 is (0,3),(0,-3)