What is the vertices (x^2}{36}-\frac{y^2)/9 =1 ?

The vertices (x^2}{36}-\frac{y^2)/9 =1 is (6,0),(-6,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices (x^2}{36}-\frac{y^2)/9 =1

vertices

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1

(6, 0), (- 6, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 3

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

4 x^{2} - y^{2} = 16

144 y^{2} - 25 x^{2} = 3600

\frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1

\frac{( y + 2 ) ^{2}}{2} - \frac{( x + 1 ) ^{2}}{2} = 1

4 x^{2} - 25 y^{2} + 16 x + 50 y - 109 = 0

What is the vertices (x^2}{36}-\frac{y^2)/9 =1 ?
The vertices (x^2}{36}-\frac{y^2)/9 =1 is (6,0),(-6,0)