What is the vertices (x^2)/(100)-(y^2)/(64)=1 ?

The vertices (x^2)/(100)-(y^2)/(64)=1 is (10,0),(-10,0)

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vertices (x^2)/(100)-(y^2)/(64)=1

vertices

\frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1

(10, 0), (- 10, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 10, b = 8

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

9 x^{2} - 18 x - 16 y^{2} - 64 y = 199

\frac{y ^{2}}{49} - \frac{x ^{2}}{16} = 1

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

\frac{( y - 3 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{16} = 1

What is the vertices (x^2)/(100)-(y^2)/(64)=1 ?
The vertices (x^2)/(100)-(y^2)/(64)=1 is (10,0),(-10,0)