What is the vertices 9x^2-25y^2=225 ?

The vertices 9x^2-25y^2=225 is (5,0),(-5,0)

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vertices 9x^2-25y^2=225

vertices

9 x^{2} - 25 y^{2} = 225

(5, 0), (- 5, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

9 x^{2} - 25 y^{2} = 225 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 3

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

\frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1

18 x^{2} - 32 y^{2} - 108 y - 128 x - 254 = 0

9 y^{2} - 25 x^{2} - 100 x - 108 y - 1 = 0

\frac{( x + 5 ) ^{2}}{4} - \frac{y ^{2}}{4} = 1

What is the vertices 9x^2-25y^2=225 ?
The vertices 9x^2-25y^2=225 is (5,0),(-5,0)