What is ((x-1)^2)/(36)-((y+2)^2)/(25)=1 ?

The solution to ((x-1)^2)/(36)-((y+2)^2)/(25)=1 is Hyperbola with (h,k)=(1,-2),a=6,b=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-1)^2)/(36)-((y+2)^2)/(25)=1

\frac{( x - 1 ) ^{2}}{36} - \frac{( y + 2 ) ^{2}}{25} = 1

(h, k) = (1, - 2), a = 6, b = 5

Solution steps

\frac{( x - 1 ) ^{2}}{36} - \frac{( y + 2 ) ^{2}}{25} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{36} - \frac{( y + 2 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{6 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 6, b = 5

\frac{x ^{2}}{3 0 ^{2}} - \frac{y ^{2}}{4 4 ^{2}} = 1

y^{2} - x^{2} = 8

y^{2} - x^{2} = 5

\frac{x ^{2}}{6} - \frac{y ^{2}}{9} = 1

y + y^{2} = x^{2}

What is ((x-1)^2)/(36)-((y+2)^2)/(25)=1 ?
The solution to ((x-1)^2)/(36)-((y+2)^2)/(25)=1 is Hyperbola with (h,k)=(1,-2),a=6,b=5