What is ((x-1)^2)/9-((y-5)^2)/(16)=1 ?

The solution to ((x-1)^2)/9-((y-5)^2)/(16)=1 is Hyperbola with (h,k)=(1,5),a=3,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-1)^2)/9-((y-5)^2)/(16)=1

\frac{( x - 1 ) ^{2}}{9} - \frac{( y - 5 ) ^{2}}{16} = 1

(h, k) = (1, 5), a = 3, b = 4

Solution steps

\frac{( x - 1 ) ^{2}}{9} - \frac{( y - 5 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{9} - \frac{( y - 5 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} - \frac{( y - 5 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 5), a = 3, b = 4

9 x^{2} - 16 y^{2} - 18 x - 64 y - 200 = 0

4 x^{2} - 16 y^{2} - 64 y - 128 = 0

x^{2} + 5^{2} = y^{2}

x^{2} - 9 y^{2} + 2 x - 5 yy - 80 = 0

500 a^{2} = 4368.932 + 500 b^{2}

What is ((x-1)^2)/9-((y-5)^2)/(16)=1 ?
The solution to ((x-1)^2)/9-((y-5)^2)/(16)=1 is Hyperbola with (h,k)=(1,5),a=3,b=4