What is ((y-5)^2)/(16)-(x-2)^2=1 ?

The solution to ((y-5)^2)/(16)-(x-2)^2=1 is Hyperbola with (h,k)=(2,5),a=4,b=1

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((y-5)^2)/(16)-(x-2)^2=1

\frac{( y - 5 ) ^{2}}{16} - (x - 2)^{2} = 1

(h, k) = (2, 5), a = 4, b = 1

Solution steps

\frac{( y - 5 ) ^{2}}{16} - (x - 2)^{2} = 1

Rewrite

\frac{( y - 5 ) ^{2}}{16} - (x - 2)^{2} = 1

in the form of a standard hyperbola equation

\frac{( y - 5 ) ^{2}}{4 ^{2}} - \frac{( x - 2 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 5), a = 4, b = 1

9 x^{2} - 5 y^{2} + 5 = 0

x^{2} - 9 y^{2} - 27 = 0

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

(y + 1)^{2} = x^{2} - x

x, x^{2} + 6 x + 34 = h (x)^{2}

What is ((y-5)^2)/(16)-(x-2)^2=1 ?
The solution to ((y-5)^2)/(16)-(x-2)^2=1 is Hyperbola with (h,k)=(2,5),a=4,b=1