What is x^2-4y^2+4=0 ?

The solution to x^2-4y^2+4=0 is Hyperbola with (h,k)=(0,0),a=1,b=2

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x^2-4y^2+4=0

x^{2} - 4 y^{2} + 4 = 0

(h, k) = (0, 0), a = 1, b = 2

Solution steps

x^{2} - 4 y^{2} + 4 = 0

Rewrite

x^{2} - 4 y^{2} + 4 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{1 ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 2

36 y^{2} - x^{2} = 9

2 x + 5 y = \frac{21}{2 x - 5 y - 11}

2 y^{2} - x^{2} = 28

\frac{( x - 4 ) ^{2}}{9} - \frac{( Y ( x ) + 1 ) ^{2}}{4} = 1

\frac{( x - 2 ) ^{2}}{16} - \frac{( y - 3 ) ^{2}}{9} = 1

What is x^2-4y^2+4=0 ?
The solution to x^2-4y^2+4=0 is Hyperbola with (h,k)=(0,0),a=1,b=2