What is 2x^2=2y^2+8 ?

The solution to 2x^2=2y^2+8 is Hyperbola with (h,k)=(0,0),a=2,b=2

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2x^2=2y^2+8

2 x^{2} = 2 y^{2} + 8

(h, k) = (0, 0), a = 2, b = 2

Solution steps

2 x^{2} = 2 y^{2} + 8

Rewrite

2 x^{2} = 2 y^{2} + 8

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 2

x^{2} - y^{2} + 2 x + 2 y - 20 = 0

1 1^{2} + x^{2} = y^{2}

\frac{( x - 5 ) ^{2}}{16} - \frac{( y - 10 ) ^{2}}{10} = 1

(x - 2)^{2} - (y - 1)^{2} = 4

4 x^{2} - 3 y^{2} + 32 x - 18 y = - 25

What is 2x^2=2y^2+8 ?
The solution to 2x^2=2y^2+8 is Hyperbola with (h,k)=(0,0),a=2,b=2