What is -((x-2)^2)/9+((y+5)^2)/7 =1 ?

The solution to -((x-2)^2)/9+((y+5)^2)/7 =1 is Hyperbola with (h,k)=(2,-5),a=sqrt(7),b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-((x-2)^2)/9+((y+5)^2)/7 =1

- \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{7} = 1

(h, k) = (2, - 5), a = 7, b = 3

Solution steps

- \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{7} = 1

Rewrite

- \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{7} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 5 ) ) ^{2}}{( 7 ) ^{2}} - \frac{( x - 2 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 5), a = 7, b = 3

(x - 2 \cdot y) \cdot (x + 2 \cdot y) = 90005

x^{2} - y^{2} = 303

\frac{( y + 3 ) ^{2}}{4} - (x - 1)^{2} = 1

(\frac{x + 2}{10})^{2} - (\frac{y + 4}{25})^{2} = 1

4 (x + 1)^{2} - 3 (y - 2)^{2} = 15

What is -((x-2)^2)/9+((y+5)^2)/7 =1 ?
The solution to -((x-2)^2)/9+((y+5)^2)/7 =1 is Hyperbola with (h,k)=(2,-5),a=sqrt(7),b=3