What is 8x^2-5y^2+96x+40y+168=0 ?

The solution to 8x^2-5y^2+96x+40y+168=0 is Hyperbola with (h,k)=(-6,4),a=sqrt(5),b=2sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8x^2-5y^2+96x+40y+168=0

8 x^{2} - 5 y^{2} + 96 x + 40 y + 168 = 0

(h, k) = (- 6, 4), a = 5, b = 22

Solution steps

8 x^{2} - 5 y^{2} + 96 x + 40 y + 168 = 0

Rewrite

8 x^{2} - 5 y^{2} + 96 x + 40 y + 168 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 6 ) ) ^{2}}{( 5 ) ^{2}} - \frac{( y - 4 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 6, 4), a = 5, b = 22

\frac{x ^{2}}{121} - \frac{y ^{2}}{9} = 1

5 x^{2} - y^{2} = 20

(y - 3)^{2} - 9 (x - 3)^{2} = 9

x^{2} - y^{2} + 6 x = 19

x^{2} - y^{2} + 6 x = 11

What is 8x^2-5y^2+96x+40y+168=0 ?
The solution to 8x^2-5y^2+96x+40y+168=0 is Hyperbola with (h,k)=(-6,4),a=sqrt(5),b=2sqrt(2)