What is 4x^2-9y^2=15 ?

The solution to 4x^2-9y^2=15 is Hyperbola with (h,k)=(0,0),a=(sqrt(15))/2 ,b=sqrt(5/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2-9y^2=15

4 x^{2} - 9 y^{2} = 15

(h, k) = (0, 0), a = \frac{15}{2}, b = \frac{5}{3}

Solution steps

4 x^{2} - 9 y^{2} = 15

Rewrite

4 x^{2} - 9 y^{2} = 15

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( \frac{15}{2} ) ^{2}} - \frac{( y - 0 ) ^{2}}{( \frac{5}{3} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{15}{2}, b = \frac{5}{3}

(x - 2)^{2} - (y + 3)^{2} = 13

\frac{( x - 6 ) ^{2}}{4} - \frac{( y + 6 ) ^{2}}{81} = 1

x^{2} - y^{2} - 8 x - 4 y - 61 = 0

x^{2} - y^{2} + x - \frac{1}{2} y + 1 = 0

9 x^{2} - y^{2} + 72 x + 108 = 0

What is 4x^2-9y^2=15 ?
The solution to 4x^2-9y^2=15 is Hyperbola with (h,k)=(0,0),a=(sqrt(15))/2 ,b=sqrt(5/3)