What is -3x^2+2y=5x+3y-8 ?

The solution to -3x^2+2y=5x+3y-8 is Parabola with (h,k)=(-5/6 , 121/12),p=-1/12

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-3x^2+2y=5x+3y-8

- 3 x^{2} + 2 y = 5 x + 3 y - 8

(h, k) = (- \frac{5}{6}, \frac{121}{12}), p = - \frac{1}{12}

Solution steps

- 3 x^{2} + 2 y = 5 x + 3 y - 8

Rewrite

- 3 x^{2} + 2 y = 5 x + 3 y - 8

in the standard form

4 (- \frac{1}{12}) (y - \frac{121}{12}) = (x - (- \frac{5}{6}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{6}, \frac{121}{12}), p = - \frac{1}{12}

y^{2} = - 5 x

4 x^{2} + 24 x - y + 38 = 0

x^{2} - 4 x - 2 y + 2 = 0

x^{2} - 8 x + 6 y + 4 = 0

y - 4 = - (x - 3)^{2}

What is -3x^2+2y=5x+3y-8 ?
The solution to -3x^2+2y=5x+3y-8 is Parabola with (h,k)=(-5/6 , 121/12),p=-1/12