What is ((y-1)^2)/(3^2)-((x-1)^2)/(2^2)=1 ?

The solution to ((y-1)^2)/(3^2)-((x-1)^2)/(2^2)=1 is Hyperbola with (h,k)=(1,1),a=3,b=2

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((y-1)^2)/(3^2)-((x-1)^2)/(2^2)=1

\frac{( y - 1 ) ^{2}}{3 ^{2}} - \frac{( x - 1 ) ^{2}}{2 ^{2}} = 1

(h, k) = (1, 1), a = 3, b = 2

Solution steps

\frac{( y - 1 ) ^{2}}{3 ^{2}} - \frac{( x - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 1), a = 3, b = 2

2 x^{2} - 4 y^{2} + 12 x + 8 y + 10 = 0

\frac{x ^{2}}{11} - \frac{y ^{2}}{16} = 1

x^{(2)} - y^{(2)} = 4

5 x^{2} - 3 y^{2} = 8

d^{2} = (3 - 10 t)^{2} + (2 - 40 t)^{2}

What is ((y-1)^2)/(3^2)-((x-1)^2)/(2^2)=1 ?
The solution to ((y-1)^2)/(3^2)-((x-1)^2)/(2^2)=1 is Hyperbola with (h,k)=(1,1),a=3,b=2