What is ((x-3)^2)/((3)^2)-((y+5)^2)/((6)^2)=1 ?

The solution to ((x-3)^2)/((3)^2)-((y+5)^2)/((6)^2)=1 is Hyperbola with (h,k)=(3,-5),a=3,b=6

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((x-3)^2)/((3)^2)-((y+5)^2)/((6)^2)=1

\frac{( x - 3 ) ^{2}}{( 3 ) ^{2}} - \frac{( y + 5 ) ^{2}}{( 6 ) ^{2}} = 1

(h, k) = (3, - 5), a = 3, b = 6

Solution steps

\frac{( x - 3 ) ^{2}}{3 ^{2}} - \frac{( y + 5 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 5), a = 3, b = 6

\frac{( ( x - 2 ) ^{2} )}{4} - \frac{( ( y + 1 ) ^{2} )}{9} = 1

5 x^{2} - 4 y^{2} - 20 = 0

4 x^{2} - 25 y^{2} + 50 y - 125 = 0

f (x) f (x) = x^{2} - x + 1

- 9 x^{2} + 4 y^{2} - 108 x + 32 y - 296 = 0

What is ((x-3)^2)/((3)^2)-((y+5)^2)/((6)^2)=1 ?
The solution to ((x-3)^2)/((3)^2)-((y+5)^2)/((6)^2)=1 is Hyperbola with (h,k)=(3,-5),a=3,b=6