What is (y^2)/3-(x^2)/(16)=1 ?

The solution to (y^2)/3-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=sqrt(3),b=4

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(y^2)/3-(x^2)/(16)=1

\frac{y ^{2}}{3} - \frac{x ^{2}}{16} = 1

(h, k) = (0, 0), a = 3, b = 4

Solution steps

\frac{y ^{2}}{3} - \frac{x ^{2}}{16} = 1

Rewrite

\frac{y ^{2}}{3} - \frac{x ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 3 ) ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 4

2500 x^{2} - 640 x + 41 = y^{2}

5 x^{2} - 3 y^{2} + 31 x + 23 y + 24 = 0

y^{2} = \frac{( 900 + 36 ( x - 8 ) ^{2} )}{25}

\frac{x ^{2}}{400} - \frac{y ^{2}}{625} = 1

3 x^{2} - 9 y^{2} - 18 x + 18 y - 54 = 0

What is (y^2)/3-(x^2)/(16)=1 ?
The solution to (y^2)/3-(x^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=sqrt(3),b=4