What is (x^2)/(2^2)-(y^2)/(4^2)=-1 ?

The solution to (x^2)/(2^2)-(y^2)/(4^2)=-1 is Hyperbola with (h,k)=(0,0),a=4,b=2

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(x^2)/(2^2)-(y^2)/(4^2)=-1

\frac{x ^{2}}{2 ^{2}} - \frac{y ^{2}}{4 ^{2}} = - 1

(h, k) = (0, 0), a = 4, b = 2

Solution steps

\frac{x ^{2}}{2 ^{2}} - \frac{y ^{2}}{4 ^{2}} = - 1

Rewrite

\frac{x ^{2}}{2 ^{2}} - \frac{y ^{2}}{4 ^{2}} = - 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 2

\frac{( x + 1 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{4} = 1

\frac{x ^{2}}{1 8 ^{2}} - \frac{y ^{2}}{3 5 ^{2}} = 1

x^{2} - 4 y^{2} - 2 x - 8 y + 1 = 0

\frac{( y - 5 ) ^{2}}{4} - \frac{( x - 2 ) ^{2}}{12} = 1

3 x^{2} - 5 y^{2} + 6 x + 10 = 32

What is (x^2)/(2^2)-(y^2)/(4^2)=-1 ?
The solution to (x^2)/(2^2)-(y^2)/(4^2)=-1 is Hyperbola with (h,k)=(0,0),a=4,b=2