x^2=16y

解答

x^{2} = 16 y

(h, k) = (0, 0), p = 4

求解步骤

x^{2} = 16 y

将

x^{2} = 16 y

改写为标准形式:

4 \cdot 4 (y - 0) = (x - 0)^{2}

因此抛物线性质是:

(h, k) = (0, 0), p = 4

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

- 9 x^{2} + 4 y^{2} - 36 x - 16 y - 164 = 0

d i rec t r i x \frac{1}{4} (y + 3) = (x - 2)^{2}

x = - 2 y^{2}

x^{2} + y^{2} = 36