What is 1*3=(a+b)(a-b) ?

The solution to 1*3=(a+b)(a-b) is Hyperbola with (h,k)=(0,0),a=sqrt(3),b=sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1*3=(a+b)(a-b)

1 \cdot 3 = (a + b) (a - b)

(h, k) = (0, 0), a = 3, b = 3

Solution steps

1 \cdot 3 = (a + b) (a - b)

Rewrite

1 \cdot 3 - (a + b) (a - b) = 0

in the form of a standard hyperbola equation

\frac{( a - 0 ) ^{2}}{( 3 ) ^{2}} - \frac{( b - 0 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 3, b = 3

x^{2} - y^{2} = - (1)

x, 2 x^{2} - 28 x + 196 = r (x)^{2}

- x^{2} + y^{2} = - 11

x^{2} - 4 y^{2} - 6 x - 16 y - 16 = 0

\frac{( x - 7 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{16} = 1

What is 1*3=(a+b)(a-b) ?
The solution to 1*3=(a+b)(a-b) is Hyperbola with (h,k)=(0,0),a=sqrt(3),b=sqrt(3)