What is (y^2)/(25)-((x+1)^2)/(16)=1 ?

The solution to (y^2)/(25)-((x+1)^2)/(16)=1 is Hyperbola with (h,k)=(-1,0),a=5,b=4

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(y^2)/(25)-((x+1)^2)/(16)=1

\frac{y ^{2}}{25} - \frac{( x + 1 ) ^{2}}{16} = 1

(h, k) = (- 1, 0), a = 5, b = 4

Solution steps

\frac{y ^{2}}{25} - \frac{( x + 1 ) ^{2}}{16} = 1

Rewrite

\frac{y ^{2}}{25} - \frac{( x + 1 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{5 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 0), a = 5, b = 4

6 x^{2} - 5 y^{2} + 36 x + 20 y - 16 = 0

5 x^{2} - 4 y^{2} = 2

y^{2} - 8 x^{2} - 2 x - y = 0

\frac{x ^{2}}{64} - \frac{y ^{2}}{16} = 1

\frac{( x - 3 ) ^{2}}{4} - \frac{y ^{2}}{25} = 1

What is (y^2)/(25)-((x+1)^2)/(16)=1 ?
The solution to (y^2)/(25)-((x+1)^2)/(16)=1 is Hyperbola with (h,k)=(-1,0),a=5,b=4