What is ((x+8)^2)/(169)-((y+9)^2)/(25)=1 ?

The solution to ((x+8)^2)/(169)-((y+9)^2)/(25)=1 is Hyperbola with (h,k)=(-8,-9),a=13,b=5

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((x+8)^2)/(169)-((y+9)^2)/(25)=1

\frac{( x + 8 ) ^{2}}{169} - \frac{( y + 9 ) ^{2}}{25} = 1

(h, k) = (- 8, - 9), a = 13, b = 5

Solution steps

\frac{( x + 8 ) ^{2}}{169} - \frac{( y + 9 ) ^{2}}{25} = 1

Rewrite

\frac{( x + 8 ) ^{2}}{169} - \frac{( y + 9 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 8 ) ) ^{2}}{1 3 ^{2}} - \frac{( y - ( - 9 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 8, - 9), a = 13, b = 5

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

9 x^{2} - 100 y^{2} = 25

4 x^{2} - 49 y^{2} - 24 x + 882 y - 4129 = 0

\frac{- y ^{2}}{4} + \frac{z ^{2}}{4} = 1 - \frac{5}{4}

+ y = x^{2} - y^{2}

What is ((x+8)^2)/(169)-((y+9)^2)/(25)=1 ?
The solution to ((x+8)^2)/(169)-((y+9)^2)/(25)=1 is Hyperbola with (h,k)=(-8,-9),a=13,b=5