What is x^2-4y^2+2x+16y-11=0 ?

The solution to x^2-4y^2+2x+16y-11=0 is Hyperbola with (h,k)=(-1,2),a=1,b=2

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x^2-4y^2+2x+16y-11=0

x^{2} - 4 y^{2} + 2 x + 16 y - 11 = 0

(h, k) = (- 1, 2), a = 1, b = 2

Solution steps

x^{2} - 4 y^{2} + 2 x + 16 y - 11 = 0

Rewrite

x^{2} - 4 y^{2} + 2 x + 16 y - 11 = 0

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{1 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 2), a = 1, b = 2

2 x^{2} - 3 y^{2} = 1

9 x^{2} - 4 y^{2} + 36 x - 16 y - 16 = 0

y^{2} = - 0.8944 + 1.125 x^{2}

\frac{( y - 1 ) ^{2}}{9} - \frac{( x - 4 ) ^{2}}{4} = 1

(5 x - 4)^{2} = (8 y + 2) \cdot y

What is x^2-4y^2+2x+16y-11=0 ?
The solution to x^2-4y^2+2x+16y-11=0 is Hyperbola with (h,k)=(-1,2),a=1,b=2