What is ((y-3)^2)/(169)-((x+2)^2)/(81)=1 ?

The solution to ((y-3)^2)/(169)-((x+2)^2)/(81)=1 is Hyperbola with (h,k)=(-2,3),a=13,b=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y-3)^2)/(169)-((x+2)^2)/(81)=1

\frac{( y - 3 ) ^{2}}{169} - \frac{( x + 2 ) ^{2}}{81} = 1

(h, k) = (- 2, 3), a = 13, b = 9

Solution steps

\frac{( y - 3 ) ^{2}}{169} - \frac{( x + 2 ) ^{2}}{81} = 1

Rewrite

\frac{( y - 3 ) ^{2}}{169} - \frac{( x + 2 ) ^{2}}{81} = 1

in the form of a standard hyperbola equation

\frac{( y - 3 ) ^{2}}{1 3 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{9 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 3), a = 13, b = 9

4 y^{2} - 9 x^{2} = 1

x^{2} - \frac{1}{2} y^{2} - \frac{1}{2} y = 0

y^{2} - 5 x^{2} + 20 x = 50

\frac{( y + 2 ) ^{2}}{9} - \frac{( x + 4 ) ^{2}}{40} = 1

4 x^{2} - 9 y^{2} + 24 x + 18 y - 9 = 0

What is ((y-3)^2)/(169)-((x+2)^2)/(81)=1 ?
The solution to ((y-3)^2)/(169)-((x+2)^2)/(81)=1 is Hyperbola with (h,k)=(-2,3),a=13,b=9