What is ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 ?

The solution to ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 is Hyperbola with (h,k)=(-1,4),a=5,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y-4)^2}{25}-\frac{(x+1)^2)/4 =1

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 1 ) ^{2}}{4} = 1

(h, k) = (- 1, 4), a = 5, b = 2

Solution steps

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 1 ) ^{2}}{4} = 1

Rewrite

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 1 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - 4 ) ^{2}}{5 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 4), a = 5, b = 2

y \frac{1}{3} y - x^{2} + 2 x = - 5

(x + 3)^{2} - (y + 2)^{2} = 9

5 (y + 3)^{2} - 4 (x - 1)^{2} = 20

\frac{( x - 3 ) ^{2}}{6} - \frac{( y - 1 ) ^{2}}{12} = 1

\frac{( y - 1 ) ^{2}}{36} - \frac{( x - 2 ) ^{2}}{64} = 1

What is ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 ?
The solution to ((y-4)^2}{25}-\frac{(x+1)^2)/4 =1 is Hyperbola with (h,k)=(-1,4),a=5,b=2