-8x^2+y^2-32x-16y=-16

解答

- 8 x^{2} + y^{2} - 32 x - 16 y = - 16

(h, k) = (- 2, 8), a = 4, b = 2

求解步骤

- 8 x^{2} + y^{2} - 32 x - 16 y = - 16

将

- 8 x^{2} + y^{2} - 32 x - 16 y = - 16

改写为标准双曲线方程形式

\frac{( y - 8 ) ^{2}}{4 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{( 2 ) ^{2}} = 1

因此双曲线的性质为:

(h, k) = (- 2, 8), a = 4, b = 2

\frac{1}{2} y^{2} = 2 x^{2} - 0.02

y^{2} - 6 x^{2} + 60 x + 2 y = 173

4 (x - 2)^{2} - (y - 1)^{2} = 63

\frac{( y + 5 ) ^{2}}{4} - \frac{( x + 2 ) ^{2}}{9} = 1

\frac{( x - 6 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1