yy=x^2-2x

解答

yy = x^{2} - 2 x

(h, k) = (1, 0), a = 1, b = 1

求解步骤

yy = x^{2} - 2 x

将

yy - x^{2} + 2 x = 0

改写为标准双曲线方程形式

\frac{( x - 1 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (1, 0), a = 1, b = 1

36 x^{2} - 64 y^{2} - 504 x + 768 y - 2844 = 0

4 x^{2} - 5 y^{2} + 8 x - 10 y + 19 = 0

16 y^{2} - 9 x^{2} - 112 y + 36 x + 124 = 0

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{4} = 1

\frac{( x - 6 ) ^{2}}{25} - (y + 1)^{2} = 1