What is ((y+4)^2)/1-((x-2)^2)/4 =1 ?

The solution to ((y+4)^2)/1-((x-2)^2)/4 =1 is Hyperbola with (h,k)=(2,-4),a=1,b=2

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((y+4)^2)/1-((x-2)^2)/4 =1

\frac{( y + 4 ) ^{2}}{1} - \frac{( x - 2 ) ^{2}}{4} = 1

(h, k) = (2, - 4), a = 1, b = 2

Solution steps

\frac{( y + 4 ) ^{2}}{1} - \frac{( x - 2 ) ^{2}}{4} = 1

Rewrite

\frac{( y + 4 ) ^{2}}{1} - \frac{( x - 2 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 4 ) ) ^{2}}{1 ^{2}} - \frac{( x - 2 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 4), a = 1, b = 2

\frac{( y - 13 ) ^{2}}{9} - \frac{( x - 10 ) ^{2}}{49} = 1

\frac{x ^{2}}{3} - \frac{y ^{2}}{3} = 1

y^{2} = x^{2} + 2 x

625 y^{2} - 400 x^{2} = 2500

y^{2} - y - x - 3 = x^{2} - x - y - 1

What is ((y+4)^2)/1-((x-2)^2)/4 =1 ?
The solution to ((y+4)^2)/1-((x-2)^2)/4 =1 is Hyperbola with (h,k)=(2,-4),a=1,b=2