What is (16y^2)/1-(25x^2)/1 =1 ?

The solution to (16y^2)/1-(25x^2)/1 =1 is Hyperbola with (h,k)=(0,0),a= 1/4 ,b= 1/5

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(16y^2)/1-(25x^2)/1 =1

\frac{16 y ^{2}}{1} - \frac{25 x ^{2}}{1} = 1

(h, k) = (0, 0), a = \frac{1}{4}, b = \frac{1}{5}

Solution steps

\frac{16 y ^{2}}{1} - \frac{25 x ^{2}}{1} = 1

Rewrite

\frac{16 y ^{2}}{1} - \frac{25 x ^{2}}{1} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( \frac{1}{4} ) ^{2}} - \frac{( x - 0 ) ^{2}}{( \frac{1}{5} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{1}{4}, b = \frac{1}{5}

- 9 x^{2} + 25 y^{2} - 72 x - 144 - 100 y = 0

\frac{( y - 5 ) ^{2}}{25} - (x - 2)^{2} = 1

\frac{( x + 1 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

x^{2} - \frac{1}{3} y^{2} = x + y

x^{2} - y^{2} + 1 = 0

What is (16y^2)/1-(25x^2)/1 =1 ?
The solution to (16y^2)/1-(25x^2)/1 =1 is Hyperbola with (h,k)=(0,0),a= 1/4 ,b= 1/5