((a+b)/(100))*(a-b)= 1/25

解答

(\frac{a + b}{100}) \cdot (a - b) = \frac{1}{25}

(h, k) = (0, 0), a = 2, b = 2

求解步骤

\frac{a + b}{100} (a - b) = \frac{1}{25}

将

\frac{a + b}{100} (a - b) = \frac{1}{25}

改写为标准双曲线方程形式

\frac{( a - 0 ) ^{2}}{2 ^{2}} - \frac{( b - 0 ) ^{2}}{2 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (0, 0), a = 2, b = 2

x^{2} + 3 x - 2 y^{2} + y - 23 = 0

\frac{( y - 8 ) ^{2}}{4} - \frac{( x - 5 ) ^{2}}{9} = 1

4 x^{2} - y^{2} - 4 y - 40 = 0

x^{2} - y^{2} + 4 x - 6 y = 6

x^{2} - 4 y^{2} - 8 x + 16 y - 36 = 0