What is (x^2)/(40)-(y^2)/(120)=1 ?

The solution to (x^2)/(40)-(y^2)/(120)=1 is Hyperbola with (h,k)=(0,0),a=2sqrt(10),b=2sqrt(30)

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(x^2)/(40)-(y^2)/(120)=1

\frac{x ^{2}}{40} - \frac{y ^{2}}{120} = 1

(h, k) = (0, 0), a = 210, b = 230

Solution steps

\frac{x ^{2}}{40} - \frac{y ^{2}}{120} = 1

Rewrite

\frac{x ^{2}}{40} - \frac{y ^{2}}{120} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 10 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 30 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 210, b = 230

y^{2} - x^{2} = \frac{4}{9}

9 x^{2} - 16 y^{2} - 36 x - 96 y - 252 = 0

y^{2} = 4 x^{2} - 9

\frac{y ^{2}}{121} - \frac{x ^{2}}{196} = 1

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{4} = 1

What is (x^2)/(40)-(y^2)/(120)=1 ?
The solution to (x^2)/(40)-(y^2)/(120)=1 is Hyperbola with (h,k)=(0,0),a=2sqrt(10),b=2sqrt(30)