What is ((y+3)^2)/4-((x-2)^2)/9 =1 ?

The solution to ((y+3)^2)/4-((x-2)^2)/9 =1 is Hyperbola with (h,k)=(2,-3),a=2,b=3

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((y+3)^2)/4-((x-2)^2)/9 =1

\frac{( y + 3 ) ^{2}}{4} - \frac{( x - 2 ) ^{2}}{9} = 1

(h, k) = (2, - 3), a = 2, b = 3

Solution steps

\frac{( y + 3 ) ^{2}}{4} - \frac{( x - 2 ) ^{2}}{9} = 1

Rewrite

\frac{( y + 3 ) ^{2}}{4} - \frac{( x - 2 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{2 ^{2}} - \frac{( x - 2 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 3), a = 2, b = 3

8 x^{2} - 5 y^{2} + 10 x + 4 = 0

2 X^{2} - 5 Y^{2} = 52

36 x^{2} - 4 y^{2} - 144 = 0

x^{2} - y^{2} + 6 x + 8 y - 75 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{1} = 1

What is ((y+3)^2)/4-((x-2)^2)/9 =1 ?
The solution to ((y+3)^2)/4-((x-2)^2)/9 =1 is Hyperbola with (h,k)=(2,-3),a=2,b=3