What is (x^2)/(16)-(y^2)/(20)=1 ?

The solution to (x^2)/(16)-(y^2)/(20)=1 is Hyperbola with (h,k)=(0,0),a=4,b=2sqrt(5)

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(x^2)/(16)-(y^2)/(20)=1

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1

(h, k) = (0, 0), a = 4, b = 25

Solution steps

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 25

4 x^{2} - y^{2} + 16 x + 16 y - 9 = 0

36 x^{2} - y^{2} - 24 x + 6 y - 41 = 0

\frac{x ^{2}}{4} + \frac{x}{2} - \frac{y ^{2}}{9} - \frac{2 y}{9} + \frac{1}{6} = 0

9 x^{2} - 9 y^{2} - 6 x + 24 y = 19

\frac{y ^{2}}{56} - \frac{x ^{2}}{56} = 1

What is (x^2)/(16)-(y^2)/(20)=1 ?
The solution to (x^2)/(16)-(y^2)/(20)=1 is Hyperbola with (h,k)=(0,0),a=4,b=2sqrt(5)