What is (x^2)/(60)-(y^2)/(40)=1 ?

The solution to (x^2)/(60)-(y^2)/(40)=1 is Hyperbola with (h,k)=(0,0),a=2sqrt(15),b=2sqrt(10)

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(x^2)/(60)-(y^2)/(40)=1

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

(h, k) = (0, 0), a = 215, b = 210

Solution steps

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

Rewrite

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 15 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 10 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 215, b = 210

\frac{x ^{2}}{2} - 2 y^{2} = 8

y^{2} = \frac{4 x ^{2} - 2}{9}

X^{2} - Y^{2} - 12 = 0

(x^{2} - y^{2}) = 23

8 y^{2} + 3 y - 9 = 8 x^{2} + 9 x - 3

What is (x^2)/(60)-(y^2)/(40)=1 ?
The solution to (x^2)/(60)-(y^2)/(40)=1 is Hyperbola with (h,k)=(0,0),a=2sqrt(15),b=2sqrt(10)