What is 4(x+5)^2-4y^2=20 ?

The solution to 4(x+5)^2-4y^2=20 is Hyperbola with (h,k)=(-5,0),a=sqrt(5),b=sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4(x+5)^2-4y^2=20

4 (x + 5)^{2} - 4 y^{2} = 20

(h, k) = (- 5, 0), a = 5, b = 5

Solution steps

4 (x + 5)^{2} - 4 y^{2} = 20

Rewrite

4 (x + 5)^{2} - 4 y^{2} = 20

in the form of a standard hyperbola equation

\frac{( x - ( - 5 ) ) ^{2}}{( 5 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 0), a = 5, b = 5

\frac{( x - 27 ) ^{2}}{6} - \frac{( y - 4 ) ^{2}}{10} = 1

x^{2} - y^{2} - 2 x - 4 y - 4 = 0

9 y^{2} - 4 x^{2} - 54 y - 8 x + 41 = 0

(x - 2)^{2} - \frac{( y - 1 ) ^{2}}{4} = 11

8 x^{2} - 15 y^{2} - 120 = 0

What is 4(x+5)^2-4y^2=20 ?
The solution to 4(x+5)^2-4y^2=20 is Hyperbola with (h,k)=(-5,0),a=sqrt(5),b=sqrt(5)