What is ((x-3)/(16))^2-((y+2)/(36))^2=1 ?

The solution to ((x-3)/(16))^2-((y+2)/(36))^2=1 is Hyperbola with (h,k)=(3,-2),a=16,b=36

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-3)/(16))^2-((y+2)/(36))^2=1

(\frac{x - 3}{16})^{2} - (\frac{y + 2}{36})^{2} = 1

(h, k) = (3, - 2), a = 16, b = 36

Solution steps

(\frac{x - 3}{16})^{2} - (\frac{y + 2}{36})^{2} = 1

Rewrite

(\frac{x - 3}{16})^{2} - (\frac{y + 2}{36})^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{1 6 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{3 6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 2), a = 16, b = 36

y^{2} = x^{2} + 16

y^{2} = x^{2} + 15

y^{2} = x^{2} + 20

\frac{x ^{2}}{3} - \frac{y ^{2}}{3} = 9

\frac{( x - 3 ) ^{2}}{36} - \frac{( y + 2 ) ^{2}}{64} = 1

What is ((x-3)/(16))^2-((y+2)/(36))^2=1 ?
The solution to ((x-3)/(16))^2-((y+2)/(36))^2=1 is Hyperbola with (h,k)=(3,-2),a=16,b=36