What is ((x+5)^2)/9-((y-3)^2)/(16)=1 ?

The solution to ((x+5)^2)/9-((y-3)^2)/(16)=1 is Hyperbola with (h,k)=(-5,3),a=3,b=4

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((x+5)^2)/9-((y-3)^2)/(16)=1

\frac{( x + 5 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{16} = 1

(h, k) = (- 5, 3), a = 3, b = 4

Solution steps

\frac{( x + 5 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 5 ) ) ^{2}}{3 ^{2}} - \frac{( y - 3 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 3), a = 3, b = 4

6 x^{2} - 9 y^{2} + 96 x + 36 y + 252 = 0

x^{2} = y^{2} + 3

\frac{( y + 4 ) ^{2}}{16} - \frac{( x - 3 ) ^{2}}{25} = 1

36 x^{2} - 64 y^{2} = 2304

16 x^{2} - 25 y^{2} - 256 x - 150 y + 399 = 0

What is ((x+5)^2)/9-((y-3)^2)/(16)=1 ?
The solution to ((x+5)^2)/9-((y-3)^2)/(16)=1 is Hyperbola with (h,k)=(-5,3),a=3,b=4