What is 2x^2-4y^2=8 ?

The solution to 2x^2-4y^2=8 is Hyperbola with (h,k)=(0,0),a=2,b=sqrt(2)

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2x^2-4y^2=8

2 x^{2} - 4 y^{2} = 8

(h, k) = (0, 0), a = 2, b = 2

Solution steps

2 x^{2} - 4 y^{2} = 8

Rewrite

2 x^{2} - 4 y^{2} = 8

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 2

3 y^{2} - 2 x^{2} - x + 5 y - 15 = 0

4 x^{2} - 9 y^{2} - 8 x - 36 y - 68 = 0

3 x^{2} - 5 y^{2} + 6 x + 10 y = 32

a^{2} - b^{2} = 12

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 4 ) ^{2}}{81} = 1

What is 2x^2-4y^2=8 ?
The solution to 2x^2-4y^2=8 is Hyperbola with (h,k)=(0,0),a=2,b=sqrt(2)