What is (x^2)/9-((y+2)^2)/4 =1 ?

The solution to (x^2)/9-((y+2)^2)/4 =1 is Hyperbola with (h,k)=(0,-2),a=3,b=2

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(x^2)/9-((y+2)^2)/4 =1

\frac{x ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

(h, k) = (0, - 2), a = 3, b = 2

Solution steps

\frac{x ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 2), a = 3, b = 2

x^{2} - z^{2} + 24 = 0

9 x^{2} - 4 y^{2} - 18 x - 16 y - 43 = 0

\frac{( x ^{2} )}{4} - \frac{( y ^{2} )}{9} = 1

\frac{( x - 2 ) ^{2}}{16} - \frac{( y + 1 ) ^{2}}{9} = 1

9 x^{2} - 16 y^{2} - 108 x + 64 y + 116 = 0

What is (x^2)/9-((y+2)^2)/4 =1 ?
The solution to (x^2)/9-((y+2)^2)/4 =1 is Hyperbola with (h,k)=(0,-2),a=3,b=2