What is -x^2+3y^2-4x+6y=28 ?

The solution to -x^2+3y^2-4x+6y=28 is Hyperbola with (h,k)=(-2,-1),a=3,b=3sqrt(3)

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-x^2+3y^2-4x+6y=28

- x^{2} + 3 y^{2} - 4 x + 6 y = 28

(h, k) = (- 2, - 1), a = 3, b = 33

Solution steps

- x^{2} + 3 y^{2} - 4 x + 6 y = 28

Rewrite

- x^{2} + 3 y^{2} - 4 x + 6 y = 28

in the form of a standard hyperbola equation

\frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{( 3 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, - 1), a = 3, b = 33

\frac{y ^{2}}{1} - \frac{x ^{2}}{15} = 1

\frac{( x - 2 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{64} = 1

- x^{2} + y^{2} = - 13

- x^{2} + y^{2} = 51

y^{2} + 3 = x^{2}

What is -x^2+3y^2-4x+6y=28 ?
The solution to -x^2+3y^2-4x+6y=28 is Hyperbola with (h,k)=(-2,-1),a=3,b=3sqrt(3)