What is (y^2)/(25)-((x-4)^2)/(16)=1 ?

The solution to (y^2)/(25)-((x-4)^2)/(16)=1 is Hyperbola with (h,k)=(4,0),a=5,b=4

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(y^2)/(25)-((x-4)^2)/(16)=1

\frac{y ^{2}}{25} - \frac{( x - 4 ) ^{2}}{16} = 1

(h, k) = (4, 0), a = 5, b = 4

Solution steps

\frac{y ^{2}}{25} - \frac{( x - 4 ) ^{2}}{16} = 1

Rewrite

\frac{y ^{2}}{25} - \frac{( x - 4 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{5 ^{2}} - \frac{( x - 4 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (4, 0), a = 5, b = 4

x^{2} - 2 y^{2} + 6 x + 4 y + 5 = 0

\frac{y ^{2}}{b ^{2}} - \frac{x ^{2}}{a ^{2}} = 1

25 y^{2} - x^{2} - 150 y - 16 x + 109 = 0

\frac{( x - 2 ) ^{2}}{4} - (y - 1)^{2} = - 1

- x^{2} + 36 y^{2} = 36

What is (y^2)/(25)-((x-4)^2)/(16)=1 ?
The solution to (y^2)/(25)-((x-4)^2)/(16)=1 is Hyperbola with (h,k)=(4,0),a=5,b=4