What is ((y+10)^2)/(36)-((x-3)^2)/(100)=1 ?

The solution to ((y+10)^2)/(36)-((x-3)^2)/(100)=1 is Hyperbola with (h,k)=(3,-10),a=6,b=10

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((y+10)^2)/(36)-((x-3)^2)/(100)=1

\frac{( y + 10 ) ^{2}}{36} - \frac{( x - 3 ) ^{2}}{100} = 1

(h, k) = (3, - 10), a = 6, b = 10

Solution steps

\frac{( y + 10 ) ^{2}}{36} - \frac{( x - 3 ) ^{2}}{100} = 1

Rewrite

\frac{( y + 10 ) ^{2}}{36} - \frac{( x - 3 ) ^{2}}{100} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 10 ) ) ^{2}}{6 ^{2}} - \frac{( x - 3 ) ^{2}}{1 0 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 10), a = 6, b = 10

33 (x - 2)^{2} - 16 (y - 5)^{2} = 528

4 x^{2} - 5 y^{2} - x + 16 y - 1 = 0

9 x^{2} - 16 y^{2} + 54 x - 32 y - 79 = 0

x, x = 3.4 h (x)^{2} - 8 h - 4 x^{2} + 8 x

x^{2} - 3 y^{2} - 3 x = y + 5

What is ((y+10)^2)/(36)-((x-3)^2)/(100)=1 ?
The solution to ((y+10)^2)/(36)-((x-3)^2)/(100)=1 is Hyperbola with (h,k)=(3,-10),a=6,b=10