What is ((x-1)^2)/9-((y+2)^2)/4 =1 ?

The solution to ((x-1)^2)/9-((y+2)^2)/4 =1 is Hyperbola with (h,k)=(1,-2),a=3,b=2

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((x-1)^2)/9-((y+2)^2)/4 =1

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

(h, k) = (1, - 2), a = 3, b = 2

Solution steps

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 3, b = 2

x^{2} - 2 y^{2} - 2 x - 8 y - 27 = 0

x, 0 = x^{2} + 2 x - 2 m (x)^{2}

\frac{( x - 1 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{64} = 1

\frac{( x + 1 ) ^{2}}{3} - \frac{( y - 1 ) ^{2}}{5} = 1

- 36 x^{2} + y^{2} = 36

What is ((x-1)^2)/9-((y+2)^2)/4 =1 ?
The solution to ((x-1)^2)/9-((y+2)^2)/4 =1 is Hyperbola with (h,k)=(1,-2),a=3,b=2